benjamimoorvf的部落格

That's damn difficult..................

In order to get blackjack,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! as the question metioned,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! an ace together with a K,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! Q,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! J or 10). There are only 2 cards. However,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 3 or more cards can add up to 21 (blackjack).

2 cards:

First card Second card
A K,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!Q,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!J,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!10

=4/52*16/51 = 0.02413273

First card Sceond
K,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!Q,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!J,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注!10 A

=16/52*4/51 = 0.02413273

Total probility for 2 cards = 0.04826546 or 4.8 %

3 cards ..........as the question assume only 2 cards,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! i don't show working here.
3 cards or more for example,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! you get 5,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 6,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! and 10 = 21. or 4 cards,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 4,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 5,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 3,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! 9 =21 . The more the no. of cards are,YouBet!你可以更轻松下注!YouBet!你可以更轻松下注! the more steps of calculation.

創作者介紹

陳惠群眶了朽稽琶

benjamimoorvf的部落格